Project: Level Up Your Ruby Judo

combinations.rb

@@ -0,0 +1,12 @@
+def combinations(arr1, arr2)
+  result = []
+  arr1.each do |word1|
+    arr2.each do |word2|
+      combo = word1 + word2
+      result << combo
+    end
+  end
+  return result
+end
+
+p combinations(["on", "in"], ["to", "rope"])

counting_game.rb

@@ -0,0 +1,28 @@
+def counting_game(friends, max_number)
+	current_number = 0
+	person_nr = 0
+	direction = 1
+	until current_number == max_number
+		current_number += 1
+		#if current number is higher than 1 and previous number was divisible by 11 then we skip one person
+		if current_number > 1 && (current_number - 1) % 11 == 0
+			person_nr += (2 * direction)
+		else
+			person_nr += direction
+		end
+
+		if person_nr > friends
+			person_nr -= friends
+		elsif person_nr < 1
+				person_nr += friends
+		end
+		#if number is divisible by 7, we change the direction for the next turn
+		if current_number % 7 == 0
+			direction = -(direction)
+		end
+
+		puts "Person nr. #{person_nr} says #{current_number}."
+	end
+end
+
+counting_game(10, 100)

factorial.rb

@@ -0,0 +1,7 @@
+def factorial(number)
+  result = 1
+  (1..number).each { |num| result *= num }
+  return result
+end
+
+puts factorial(5)

is_prime.rb

@@ -0,0 +1,9 @@
+def is_prime?(number)
+  (2..Math.sqrt(number).round).each do |div|
+    return false if number % div == 0
+  end
+  return true
+end
+
+puts is_prime?(7)
+puts is_prime?(14)

overlap.rb

@@ -0,0 +1,6 @@
+def overlap(rect1, rect2)
+  rect1[0][0] < rect2[1][0] && rect1[1][1] > rect2[0][1] && rect1[1][0] > rect2[0][0] && rect1[0][1] < rect2[1][1]
+end
+
+puts overlap( [ [0,0],[3,3] ], [ [1,1],[4,5] ] )
+puts overlap( [ [0,0],[1,4] ], [ [1,1],[3,2] ] )

power.rb

@@ -0,0 +1,7 @@
+def power(base, exponent)
+  result = 1
+  exponent.times { result *= base }
+  return result
+end
+
+puts power(3,4)

uniques.rb

@@ -0,0 +1,9 @@
+def uniques(array)
+  result = []
+  array.each do |item|
+    result << item unless result.include?(item)
+  end
+  return result
+end
+
+p uniques([1,5,"frog", 2,1,3,"frog"])