LeetCode Binary String With Substrings Representing 1 to N #204
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📝 WalkthroughWalkthroughThe changes reorganize problem documentation by relocating a README file to a new directory structure, update the repository index to reflect a newly added problem (1065) with a "Binary & Bit Manipulation" subsection, and export a function previously kept internal in the TypeScript implementation file. Changes
Estimated code review effort🎯 2 (Simple) | ⏱️ ~10 minutes Poem
🚥 Pre-merge checks | ✅ 2 | ❌ 1❌ Failed checks (1 warning)
✅ Passed checks (2 passed)
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Claude finished @pertrai1's task in 1m 32s —— View job LeetCode Solution Review: Binary String With Substrings Representing 1 To N✅ Algorithm CorrectnessThe solution is correct for small values of What the solution does:
Edge cases handled:
Edge cases NOT properly handled:
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🧮 Solution AnalysisPR: LeetCode Binary String With Substrings Representing 1 to N 📊 Code Quality ResultsESLint Analysis
🔍 Complexity Analysis💡 Analysis Tips
📁 Analysis Files CreatedDetailed analysis files have been automatically generated and committed to 🎯 Next Steps
Analysis generated for PR files only |
✅ Test ResultsTests have been executed for this pull request. 📊 Coverage Summary
Check the workflow logs for detailed test output. |
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🤖 Gemini Code Review (Model: This review focuses on the provided TypeScript solution for the LeetCode problem "Binary String With Substrings Representing 1 To N". 1. Pattern IdentificationThis solution primarily uses a Direct Simulation / Brute Force approach combined with String Searching. It directly iterates through each number from 1 to 2. Complexity Verification
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🤖 Gemini Code Review (Model: This is a good, straightforward attempt at solving the problem. However, a deeper look into the constraints and typical performance expectations for LeetCode problems reveals some important considerations. 1. Pattern IdentificationThis solution uses a Direct Simulation / Brute Force approach combined with String Manipulation. It directly translates the problem statement into code: iterate through each number from 1 to It doesn't employ more complex algorithmic patterns like Dynamic Programming, Two Pointers, or Graph Traversal. 2. Complexity VerificationTime Complexity
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![github-actions[bot]](https://avatars.githubusercontent.com/in/15368?s=60&v=4){kind=small}
| @@ -1,9 +1,9 @@ | |||
| function queryString(s: string, n: number): boolean { | |||
| export function queryString(s: string, n: number): boolean { | |||
| for (let i = 1; i <= n; i++) { | |||
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n times, which can be up to 10^9 according to the constraints. This will cause Time Limit Exceeded (TLE) on LeetCode.
Why this is a problem:
- With
n = 1,000,000,000, you're performing 1 billion iterations - Each iteration does a string search (
.includes()) which is O(m) where m = s.length
Suggested optimization:
// Add early termination for impossible cases
if (n >= (1 << s.length)) return false;
// Or: Iterate backwards from n (larger numbers are more restrictive)
for (let i = n; i >= 1; i--) {
// ...
}The key insight is that if s.length = 1000, it's mathematically impossible to contain all binary representations if n is too large. Consider adding bounds checking!
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Pull request overview
This PR adds a new LeetCode medium problem solution: "Binary String With Substrings Representing 1 To N". The solution was properly moved from the root directory to the correct location under leetcode/medium/ and the repository documentation was updated accordingly.
Changes:
- Added TypeScript solution for problem 1065 with proper exports
- Created clean, well-formatted README with problem description, examples, and constraints
- Updated root README.md to reflect the new problem count (171 total, 77 medium)
- Added new "Binary & Bit Manipulation" category in the Medium Problems section
Reviewed changes
Copilot reviewed 4 out of 4 changed files in this pull request and generated no comments.
| File | Description |
|---|---|
leetcode/medium/1065-binary-string-with-substrings-representing-1-to-n/binary-string-with-substrings-representing-1-to-n.ts |
Added TypeScript solution with export, proper formatting, and correct function signature |
leetcode/medium/1065-binary-string-with-substrings-representing-1-to-n/README.md |
Created clean problem documentation with markdown formatting instead of HTML |
README.md |
Updated problem counts (170→171, 76→77), added new Binary & Bit Manipulation category, and linked the new problem |
1065-binary-string-with-substrings-representing-1-to-n/README.md |
Removed old file from incorrect root location |
Comments suppressed due to low confidence (1)
leetcode/medium/1065-binary-string-with-substrings-representing-1-to-n/binary-string-with-substrings-representing-1-to-n.ts:7
- The algorithm has a potential performance issue for large values of n. With the constraint
1 <= n <= 10^9, this solution could perform up to 1 billion iterations.
Consider adding an early termination optimization: A binary string of length L can contain at most L*(L+1)/2 distinct substrings. For the given constraints where s.length <= 1000, this means approximately 500,000 possible substrings. Therefore, if n > 500,000, the function could return false immediately without iterating.
Additionally, larger numbers have longer binary representations. If n > 2^s.length, it's impossible for s to contain the binary representation of n since that binary string would be longer than s itself.
![coderabbitai[bot]](https://avatars.githubusercontent.com/in/347564?s=60&v=4){kind=small}
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Actionable comments posted: 1
Caution
Some comments are outside the diff and can’t be posted inline due to platform limitations.
⚠️ Outside diff range comments (1)
README.md (1)
184-239: Fix the problem number: 1065 is incorrect; the problem is LeetCode 1016.The slug "binary-string-with-substrings-representing-1-to-n" corresponds to LeetCode problem 1016, not 1065. Update both the problem entry and its directory path from
leetcode/medium/1065-binary-string-with-substrings-representing-1-to-ntoleetcode/medium/1016-binary-string-with-substrings-representing-1-to-n.
🤖 Fix all issues with AI agents
In
`@leetcode/medium/1065-binary-string-with-substrings-representing-1-to-n/binary-string-with-substrings-representing-1-to-n.ts`:
- Around line 1-9: The current queryString loop over i from 1..n will TLE for
large n; instead, in function queryString enumerate all substrings of s with
length up to maxLen = Math.floor(Math.log2(n)) + 1, compute their integer values
using a rolling/bit-shift approach, mark values ≤ n in a Set (or boolean array),
and early-return true when the count of seen values reaches n (otherwise return
false at end); also add an explicit top-line comment stating the pattern used
and time/space complexity. Use the unique symbol queryString and reference
maxLen, rolling value, and the seen set in the fix.
| export function queryString(s: string, n: number): boolean { | ||
| for (let i = 1; i <= n; i++) { | ||
| const str = i.toString(2); | ||
| if (!s.includes(str)) { | ||
| return false; | ||
| } | ||
| } | ||
| } | ||
| return true; | ||
| }; | ||
| } |
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Current loop up to n will TLE for large inputs.
With n up to 1e9, the for (let i = 1; i <= n; i++) approach is infeasible. A common fix is to enumerate substrings up to maxLen = floor(log2 n)+1, record values ≤ n, and early-return when all are covered. Also add explicit pattern + complexity comments as required for LeetCode TS solutions. As per coding guidelines.
⚡ Proposed fix (substring enumeration with rolling value)
-export function queryString(s: string, n: number): boolean {
- for (let i = 1; i <= n; i++) {
- const str = i.toString(2);
- if (!s.includes(str)) {
- return false;
- }
- }
- return true;
-}
+/**
+ * Pattern: substring enumeration with rolling binary value.
+ * Time: O(m * L), where m = s.length and L = floor(log2(n)) + 1.
+ * Space: O(min(n, m * L)) for the seen set.
+ */
+export function queryString(s: string, n: number): boolean {
+ const maxLen = Math.floor(Math.log2(n)) + 1;
+ if (s.length < maxLen) return false;
+
+ const seen = new Set<number>();
+ let covered = 0;
+
+ for (let i = 0; i < s.length; i++) {
+ let value = 0;
+ for (let j = i; j < s.length && j - i + 1 <= maxLen; j++) {
+ value = (value << 1) + (s[j] === "1" ? 1 : 0);
+ if (value > n) break;
+ if (value >= 1 && !seen.has(value)) {
+ seen.add(value);
+ covered++;
+ if (covered === n) return true;
+ }
+ }
+ }
+
+ return covered === n;
+}📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
| export function queryString(s: string, n: number): boolean { | |
| for (let i = 1; i <= n; i++) { | |
| const str = i.toString(2); | |
| if (!s.includes(str)) { | |
| return false; | |
| } | |
| } | |
| } | |
| return true; | |
| }; | |
| \ No newline at end of file | |
| } | |
| /** | |
| * Pattern: substring enumeration with rolling binary value. | |
| * Time: O(m * L), where m = s.length and L = floor(log2(n)) + 1. | |
| * Space: O(min(n, m * L)) for the seen set. | |
| */ | |
| export function queryString(s: string, n: number): boolean { | |
| const maxLen = Math.floor(Math.log2(n)) + 1; | |
| if (s.length < maxLen) return false; | |
| const seen = new Set<number>(); | |
| let covered = 0; | |
| for (let i = 0; i < s.length; i++) { | |
| let value = 0; | |
| for (let j = i; j < s.length && j - i + 1 <= maxLen; j++) { | |
| value = (value << 1) + (s[j] === "1" ? 1 : 0); | |
| if (value > n) break; | |
| if (value >= 1 && !seen.has(value)) { | |
| seen.add(value); | |
| covered++; | |
| if (covered === n) return true; | |
| } | |
| } | |
| } | |
| return covered === n; | |
| } |
🤖 Prompt for AI Agents
In
`@leetcode/medium/1065-binary-string-with-substrings-representing-1-to-n/binary-string-with-substrings-representing-1-to-n.ts`
around lines 1 - 9, The current queryString loop over i from 1..n will TLE for
large n; instead, in function queryString enumerate all substrings of s with
length up to maxLen = Math.floor(Math.log2(n)) + 1, compute their integer values
using a rolling/bit-shift approach, mark values ≤ n in a Set (or boolean array),
and early-return true when the count of seen values reaches n (otherwise return
false at end); also add an explicit top-line comment stating the pattern used
and time/space complexity. Use the unique symbol queryString and reference
maxLen, rolling value, and the seen set in the fix.
📅 Spaced Repetition Reviews Scheduled!Great job solving #1065 - Binary String With Substrings Representing 1 To N! 🎉 To help you retain this knowledge long-term, I've scheduled 5 review sessions using spaced repetition:
What to expect:
🧠 Why Spaced Repetition?Research shows that reviewing material at increasing intervals dramatically improves retention. This adaptive scheduling ensures optimal spacing based on when you actually complete each review! Check |
…s Representing 1 To N Problem: #1065 - Binary String With Substrings Representing 1 To N PR: #204 First review scheduled (subsequent reviews auto-scheduled on completion) [skip ci]
Summary by CodeRabbit
New Features
Documentation
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