Gulp.js command execution for humans.
As opposed to similar plugins or to
child_process.exec(),
this uses Execa which provides:
- Better Windows support, including shebangs
- Faster and more secure commands, since no shell is used by default
- Execution of locally installed binaries
- Interleaved
stdout/stderr
gulp-execa adds Gulp-specific features to
Execa including:
- a task shortcut syntax
- configurable verbosity
- better errors
Commands can be executed either directly or inside a files stream. In streaming mode, unlike other libraries:
- commands are run in parallel, not serially
- output can be saved either in files or in variables
gulpfile.js:
import { pipeline } from 'node:stream/promises'
import gulp from 'gulp'
import { exec, stream, task } from 'gulp-execa'
export const audit = task('npm audit')
export const outdated = async () => {
await exec('npm outdated')
}
export const sort = () =>
pipeline(
gulp.src('*.txt'),
stream(({ path }) => `sort ${path}`),
gulp.dest('sorted'),
)npm install -D gulp-execa
This plugin requires Gulp 5 and Node.js >=18.18.0. It is an ES module and must
be loaded using
an import or import() statement,
not require(). If TypeScript is used, it must be configured to
output ES modules,
not CommonJS.
Returns a Gulp task that executes command.
import { task } from 'gulp-execa'
export const audit = task('npm audit')Executes command. The return value is both a promise and a
child_process instance.
The promise will be resolved with the
command result. If
the command failed, the promise will be rejected with a nice
error. If the
reject: false option was used,
the promise will be resolved with that error instead.
import { exec } from 'gulp-execa'
export const outdated = async () => {
await exec('npm outdated')
}Returns a stream that executes a command on each input file.
function must:
- take a Vinyl file
as argument. The most useful property is
file.pathbut other properties are available as well. - return either:
- a
commandstring - an
optionsobject with acommandproperty undefined
- a
import { pipeline } from 'node:stream/promises'
import gulp from 'gulp'
import { stream } from 'gulp-execa'
export const sort = () =>
pipeline(
gulp.src('*.txt'),
stream(({ path }) => `sort ${path}`),
gulp.dest('sorted'),
)Each file in the stream will spawn a separate process. This can consume lots of resources so you should only use this method when there are no alternatives such as:
- firing a command programmatically instead of spawning a child process
- passing several files, a directory or a globbing pattern as arguments to the command
The debug,
stdout,
stderr,
all and
stdio options cannot be used
with this method.
By default no shell interpreter (like Bash or cmd.exe) is used. This means
command must be just the program and its arguments. No escaping/quoting is
needed, except for significant spaces (with a backslash).
Shell features such as globbing, variables and operators (like && > ;)
should not be used. All of this can be done directly in Node.js instead.
Shell interpreters are slower, less secure and less cross-platform. However, you
can still opt-in to using them with the
shell option.
import { writeFileStream } from 'node:fs'
import gulp from 'gulp'
import { task } from 'gulp-execa'
// Wrong
// export const check = task('npm audit && npm outdated')
// Correct
export const check = gulp.series(task('npm audit'), task('npm outdated'))
// Wrong
// export const install = task('npm install > log.txt')
// Correct
export const install = task('npm install', {
stdout: writeFileStream('log.txt'),
})options is an optional object.
All Execa options can be used. Please refer to its documentation for a list of possible options.
The following options are available as well.
Type: boolean
Default: debug option's value
Whether the command should be printed on the console.
$ gulp audit
[13:09:39] Using gulpfile ~/code/gulpfile.js
[13:09:39] Starting 'audit'...
[13:09:39] [gulp-execa] npm audit
[13:09:44] Finished 'audit' after 4.96 sType: boolean
Default: true for task() and
exec(), false for
stream().
Whether both the command and its output (stdout/stderr) should be printed
on the console instead of being returned in JavaScript.
$ gulp audit
[13:09:39] Using gulpfile ~/code/gulpfile.js
[13:09:39] Starting 'audit'...
[13:09:39] [gulp-execa] npm audit
== npm audit security report ===
found 0 vulnerabilities
in 27282 scanned packages
[13:09:44] Finished 'audit' after 4.96 sType: string
Value: 'replace' or 'save'
Default: 'replace'
With stream(), whether the command result should:
replacethe file's contentssave: be pushed to thefile.execaarray property
import { pipeline } from 'node:stream/promises'
import gulp from 'gulp'
import { stream } from 'gulp-execa'
import through from 'through2'
export const task = () =>
pipeline(
gulp.src('*.js'),
// Prints the number of lines of each file
stream(({ path }) => `wc -l ${path}`, { result: 'save' }),
through.obj((file, encoding, func) => {
console.log(file.execa[0].stdout)
func(null, file)
}),
)Type: string
Value: 'stdout', 'stderr' or 'all'
Default: 'stdout'
Which output stream to use with result: 'replace'.
import { pipeline } from 'node:stream/promises'
import gulp from 'gulp'
import { stream } from 'gulp-execa'
import through from 'through2'
export const task = () =>
pipeline(
gulp.src('*.js'),
// Prints the number of lines of each file, including `stderr`
stream(({ path }) => `wc -l ${path}`, { result: 'replace', from: 'all' }),
through.obj((file, encoding, func) => {
console.log(file.contents.toString())
func(null, file)
}),
)Type: integer
Default: 100
With stream(), how many commands to run in parallel
at once.
For any question, don't hesitate to submit an issue on GitHub.
Everyone is welcome regardless of personal background. We enforce a Code of conduct in order to promote a positive and inclusive environment.
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Thanks go to our wonderful contributors:
ehmicky π» π¨ π€ π | Jonathan Haines π |