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constructbinarytreefrompreorderandinorder.cpp
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73 lines (73 loc) · 1.84 KB
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/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder) {
int lenp = preorder.size();
int leni = inorder.size();
if (lenp != leni ||
lenp == 0)
{
return NULL;
}
queue<TreeNode*>pTree;
for (int i = 0; i < lenp; i++)
{
pTree.push(new TreeNode(preorder[i]));
}
return genTree(pTree, inorder, 0, leni - 1);
}
private:
TreeNode *genTree(queue<TreeNode*>&pTree, vector<int> &inorder, int start, int end)
{
if (pTree.empty())
{
return NULL;
}
auto root = pTree.front();
pTree.pop();
if (pTree.empty())
{
return root;
}
if (start == end)
{
return root;
}
int index = find(inorder, start, end, root->val);
if (index == start)
{
root->left = NULL;
root->right = genTree(pTree, inorder, start +1 , end);
}
else if (index == end)
{
root->left = genTree(pTree, inorder, start, end - 1);
root->right = NULL;
}
else
{
root->left = genTree(pTree, inorder, start, index - 1);
root->right = genTree(pTree, inorder, index + 1, end);
}
return root;
}
int find(vector<int>p, int st, int end, int num)
{
for (int i = st; i <= end; i++)
{
if (p[i] == num)
{
return i;
}
}
return end + 1;
}
};