Add generic type fallback for multiple dispatch! v1.2.4

When you call spelled_out with an unknown number type, it should tell
you that it's not supported, rather than doing the Pythonic thing of
trying to use it until it fails with a poor error message.  Multiple
dispatch is very convenient to use in this case, but we need to
specify the fallback function manually.  This is what is implemented
in this version of SpelledOut.jl

See merge request #61

Author: jakewilliami

Project.toml

@@ -1,7 +1,7 @@
 name = "SpelledOut"
 uuid = "4728c690-e668-4265-bc0d-51a8c0f93067"
 authors = ["Jake W. Ireland <[email protected]> and contributors"]
-version = "1.2.3"
+version = "1.2.4"
 
 [deps]
 DecFP = "55939f99-70c6-5e9b-8bb0-5071ed7d61fd"

src/es.jl

@@ -92,7 +92,7 @@ function es_spell_large(_number)
 end
 
 
-function spelled_out_es(number; dict=:standard)
+function spelled_out_es(number::Union{Integer, Float64}; dict=:standard)
     if iszero(number)
         return "cero"
     end
@@ -135,3 +135,7 @@ end
 
 
 
+# Fallback method if we do not know how to handle the input
+function spelled_out_es(number, dict = :standard)
+    throw(error("Cannot parse type $(typeof(number)).  Please make an issue."))
+end

src/pt.jl

@@ -120,7 +120,7 @@ function pt_spell_large( _number; portugal::Bool = false )
     return res
 end
 
-function spelled_out_pt( number; portugal::Bool = false, dict::Symbol = :standard )
+function spelled_out_pt( number::Union{Integer, Float64}; portugal::Bool = false, dict::Symbol = :standard )
     if iszero( number )
         return "zero"
     end
@@ -156,3 +156,7 @@ function spelled_out_pt( number; portugal::Bool = false, dict::Symbol = :standar
 end
 
 
+# Fallback method if we do not know how to handle the input
+function spelled_out_pt(number; portugal::Bool = false, dict::Symbol = :standard)
+    throw(error("Cannot parse type $(typeof(number)).  Please make an issue."))
+end

src/ru.jl

@@ -1,3 +1,9 @@
 function spelled_out_ru(number::Number)
 
+
+end
+
+# Fallback method if we do not know how to handle the input
+function spelled_out_ru(number)
+    throw(error("Cannot parse type $(typeof(number)).  Please make an issue."))
 end