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MaximumSubarray.java
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35 lines (33 loc) · 1.03 KB
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package leetcode;
/**
* @author eko
*
* Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
*
* Example:
*
* Input: [-2,1,-3,4,-1,2,1,-5,4],
* Output: 6
* Explanation: [4,-1,2,1] has the largest sum = 6.
* Follow up:
*
* If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
*
*/
public class MaximumSubarray {
public static void main(String[] args) {
int[] nums = new int[]{-2,1,-3,4,-1,2,1,-5,4};
System.out.println(new MaximumSubarray().maxSubArray(nums));
}
public int maxSubArray(int[] nums) {
if (nums.length == 0) return 0;
int[] maxNums = new int[nums.length];
int max = nums[0];
maxNums[0] = nums[0];
for (int i = 1; i < nums.length; i++) {
maxNums[i] = nums[i] + (maxNums[i-1] > 0 ? maxNums[i-1] : 0);
max = Math.max(max, maxNums[i]);
}
return max;
}
}