-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathdiameter_of_binary_tree.py
More file actions
58 lines (40 loc) · 1.33 KB
/
diameter_of_binary_tree.py
File metadata and controls
58 lines (40 loc) · 1.33 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int:
largestdiam = 0
def height(root):
if not root:
return 0
nonlocal largestdiam
leftheight = height(root.left)
rightheight = height(root.right)
diameter = leftheight + rightheight
largestdiam = max(largestdiam, diameter)
return 1 + max(leftheight,rightheight)
height(root)
return largestdiam
"""
543. Diameter of Binary Tree
Solved
Easy
Topics
Companies
Given the root of a binary tree, return the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
The length of a path between two nodes is represented by the number of edges between them.
Example 1:
Input: root = [1,2,3,4,5]
Output: 3
Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].
Example 2:
Input: root = [1,2]
Output: 1
Constraints:
The number of nodes in the tree is in the range [1, 104].
-100 <= Node.val <= 100
"""