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lines changed Original file line number Diff line number Diff line change @@ -275,7 +275,7 @@ if __name__ == "__main__":
275275
276276即可确定最终的密码为 ` 2w9lMSElHLSu6PigGsugLYdKiLV9BH84 `
277277
278- ## Level 1
278+ ## Level 0 -> Level 1
279279
280280登录 ` Level 0 ` 账户
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@@ -338,7 +338,7 @@ for i in $(seq 10000);do rm /tmp/randark/12341;echo 1234 > /tmp/randark/12341;rm
338338
339339即可确定最终的密码为 ` WUJPXwIoiBhedmDZceQ5DAUMq0JeI0eU `
340340
341- ## Level 2
341+ ## Level 1 -> Level 2
342342
343343登录 ` Level 1 ` 账户
344344
@@ -554,7 +554,7 @@ for i in $(seq 1000);do echo $i; /formulaone/formulaone2 ;done
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555555即可确定最终的密码为 ` OvQAKUM3BrvbH4pKjBJBCOUpTGSDjNum `
556556
557- ## Level 3
557+ ## Level 2 -> Level 3
558558
559559登录 ` Level 2 ` 账户
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@@ -802,11 +802,22 @@ int main(int argc, char *argv[])
802802
803803```
804804
805+ 开两个 SSH 会话,各自执行
806+
807+ ```shell
808+ # compiled from c code above
809+ ./exp
810+
811+ for i in $(seq 1000);do echo $i; /formulaone/formulaone3 D ;done
812+ ```
813+
814+ 理想情况下,应该在 10 次循环内成功(竞争看运气)
815+
805816![ img] ( img/image_20250118-161823.png )
806817
807818即可确定最终的密码为 ` Liqb5fEvP7IjKWZpoFOdYfQT494msxyv `
808819
809- ## Level 5
820+ ## Level 3 -> Level 5
810821
811822登录 ` Level 3 ` 账户
812823
818829
819830``` c
820831/*
821- * -( nemo1.c )-
832+ * -(nemo1.c)-
822833 * by nemo 2005
823834 *
824835 * v0.2
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