Is there any way to get a parent symbol through parent scope in Pyslang

[edwinsun5278]

hello, is there any way to get a parent symbol through parent scope in Pyslang.?
thank you

[MikePopoloski]

The parent scope is also a symbol. What have you tried, what exactly isn't working?

[edwinsun5278]

Hi, MikePopoloski, Thank you for your reply.

https://github.com/MikePopoloski/slang/blob/master/source/ast/Symbol.cpp , 197 line
in slang (C++), I kown i can use asSymbol() method to get the parent symbol through parent scope
like :
auto& parent = symbol.getParentScope()->asSymbol();
but in pyslang, I got a symbol 's parent scopt like sym_parentscope = symbol.parentScope. but it seems that there is no mehtod to convert sym_parentscope to a symbol. Could you please give some ideas like use using asSymbol(C++ Method) in Pyslang

[MikePopoloski]

Ah, all Scopes are also Symbols. In C++ land you need the extra cast but because Python is dynamic it's literally just the same object.

[edwinsun5278]

@MikePopoloski

Okey, Thanks for your reply!, I got it.

Like def_property_readonly("parentSymbol", &Scope::asSymbol) , if asSymbol Method is binded in Python, it seems better to get symbol
like C++ auto& parent = symbol.getParentScope()->asSymbol();

py::class_(m, "Scope")
.def_property_readonly("compilation", &Scope::getCompilation)
.def_property_readonly("defaultNetType", &Scope::getDefaultNetType)
.def_property_readonly("timeScale", &Scope::getTimeScale)
.def_property_readonly("isProceduralContext", &Scope::isProceduralContext)
.def_property_readonly("containingInstance", &Scope::getContainingInstance)
.def_property_readonly("compilationUnit", &Scope::getCompilationUnit)
.def_property_readonly("isUninstantiated", &Scope::isUninstantiated)
.def_property_readonly("parentSymbol", &Scope::asSymbol)